Question

sum of series of 1/6+1/36/+1/216 to n terms​

Answer 1

Answer:

43/216

mark me as brainliest

Answer 2

Answer:

Sum upto n terms is (6^n-1)/(5×6^n).

Step-by-step explanation:

The series is in decreasing G. P

So, sum upto n terms is

$a(1 - {r}^{n} )\div 1 - r$

Here a=1/6 and r=1/6