Sum of squares of 2 consecutive odd number of 290 find the number
Answers
Answered by
1
Answer:
11 and 13
-11 and -13
Step-by-step explanation:
Let one number is x.
The other number would be x+2
(x)^2 + (x+2)^2 = 290
x^2 + x^2 + 4x + 4 = 290
2x^2 + 4x + 4 - 290 = 0
2x^2 + 4x - 286 = 0
x^ 2 + 2x - 143 = 0
x^2 + 13x - 11x - 143 =0
x(x + 13) - 11(x+13) = 0
(x-11)(x+13) = 0
x = 11
x = -13
Similar questions