Sum of squares of the two consecutive natural number is 421
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421/2 it will be in point so 421 +1 =422/2=211 Now 211 first value second = 211-1=210 211+210 421
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Let two consecutive natural numbers be x and x + 1
⇒ x² + (x+1)² = 421
⇒ x² + x² + 2x + 1 - 421 = 0
⇒ 2x² + 2x - 420 = 0
⇒ x² + x - 210 = 0
⇒ (x+15)(x-14) = 0
x = 14 its consecutive is 15
Two numbers are 14 and 15
⇒ x² + (x+1)² = 421
⇒ x² + x² + 2x + 1 - 421 = 0
⇒ 2x² + 2x - 420 = 0
⇒ x² + x - 210 = 0
⇒ (x+15)(x-14) = 0
x = 14 its consecutive is 15
Two numbers are 14 and 15
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