Sum of the 4+8+12+.............................+52 is?
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Answer:
in this pair the table of 4 is there 4 +8+12+16+20+24+28+32+36+40+44+48+52 = 364
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here
A=4 ,d=4(8-4),An=52 , n=?
An=a+(n-1)d
52=4+(n-1)4
48/4=n-1
12-1=n
11
now,
Sn=n/2(2a+(n-1)d
Sn=11/2(48)
Sn=24×11
Sn=264
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