Question

sum of the age of father and son is 75 years. five years ago the age of father was 5 years more than twice the age of son​

Answer 1

Answer:

please Mark it as brainliest answer

Answer 2

$Let\:Present \:age \: of \: son = x \: years$

$Present \:age \: of \: Father = (75-x) \: years$

$\underline {\pink{5 \: years \:ago :}}$

$Age \: of \: son = ( x - 5 ) \: years$

$Age \:of \: father = ( 75-x-5)\: years$

$= (70 - x )\: years$

/* According to the problem given */

$Age \:of \: father = 2\times (age \:of \:son ) + 5$

$\implies 70-x = 2(x-5) + 5$

$\implies 70-x = 2x - 10 + 5$

$\implies 70-x = 2x - 5$

$\implies - x - 2x = -5 - 70$

$\implies -3x = -75$

$\implies x = \frac{-75}{-3}$

$\implies x = 25$

Therefore.,

$\red{ Present \:age \: of \: son} \green { = 25 \:years }$

$\red{ Present \:age \: of \: father}$

$= (75 - x )$

$= 75 - 25$

$\green { = 50 \:years }$

•••♪