Question

· Sum of the ages of father and his daughter is 70 years. After 10 years father will be twice as old as his daughter. Find their present ages.​

Answer 1

Answer:

Step-by-step explanation:

Let

Present age of father = f

Present age of son = s

The sum of ages of a father and son is 70.

f+s=70

f=70-s...........(1)

In ten years time

Father will be = f+10

Son will be = s+10

Then

The father will be twice as old as his son

f+10=2(s+10)

f+10=2s+20

f=2s+20-10

f=2s+10.................(2)

Put the value of f from (1) to (2)

70-s=2s+10

-s-2s=10-70

-3s=-60

-3s/-3=-60/-3

s=20

Put the value of s in (1)

f=70-s...........(1)

f=70-20

f=50

Present age of father = f = 50

Present age of son = s = 20