Sum of the ages of son and his father is 35 and the product of their ages is 150 . find their ages
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Let. son's age is x
dad's age is y
See , as they said d sum so , we have to add he ages of dad and his son and mention the sum .As follows .
x+y=35
And next they said about product . We get product by multiplying two factors so,
x × y = 150
xy= 150
so here we got two equations :
x+y= 35----(1)
xy= 150----(2)
Based on mathematics we have two methods to solve linear equation ,
They are :
Substitution method ,
Elimination method.
So, let us try first and easy method substitution method
In substitution method we consider equation -1 as , x+y= 35
And second equation as , xy=150
from eq--(2)
xy= 150
y=150÷x
In the above eq we got present value of "y".
So, we have to substitute in eq--(1 )
x+y= 35
x+ 150÷x= 35
x^2+150= 35x
x^2-35x+150= 0
Sorry you have to factorize and know the value of 'x' and subtitute in any other eq b/w 1 and 2
dad's age is y
See , as they said d sum so , we have to add he ages of dad and his son and mention the sum .As follows .
x+y=35
And next they said about product . We get product by multiplying two factors so,
x × y = 150
xy= 150
so here we got two equations :
x+y= 35----(1)
xy= 150----(2)
Based on mathematics we have two methods to solve linear equation ,
They are :
Substitution method ,
Elimination method.
So, let us try first and easy method substitution method
In substitution method we consider equation -1 as , x+y= 35
And second equation as , xy=150
from eq--(2)
xy= 150
y=150÷x
In the above eq we got present value of "y".
So, we have to substitute in eq--(1 )
x+y= 35
x+ 150÷x= 35
x^2+150= 35x
x^2-35x+150= 0
Sorry you have to factorize and know the value of 'x' and subtitute in any other eq b/w 1 and 2
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