Question

Sum of the area of two square is 468 m if the difference of their perimeter is 24 m find the side of two square

Answer 1

Answer:

Let the side of the first square be 'a'm and that of the second be 'A' m.

Area of the first square =a^2 sq m.

Area of the second square =A^2 sq m.

Their perimeters would be 4a and 4A respectively.

Given 4A−4a=24

A−a=6 --(1)

A^2+ a^2=468 --(2)

From (1), A=a+6

Substituting for A in (2), we get

(a+6)^2 +a^2=468

a^2+12a+36+a^2=468

2a^2+12a+36=468

a^2+6a+18=234

a^2+6a−216=0

a^2+18a−12a−216=0

a(a+18)−12(a+18)=0

(a−12)(a+18)=0

a=12,−18

So, the side of the first square is 12 m. and the side of the second square is 18 m.

Step-by-step explanation:

Hope this helps you...