Sum of the areas of the two square is 468m2. If the difference of their perimeter is 24m, formulate the quadratic equation to find the side of the square.
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Answered by
4
Answer:
!!
Step-by-step explanation:
Let the side of the larger square be x.
Let the side of the smaller square be y.
APQ x2+y2 = 468
Cond. II
4x-4y = 24
=> x – y = 6
=> x = 6 + y
x2 + y2 = 468
=> (6+y)2 +y2 = 468
on solving we get y = 12
=> x = (12+6) = 18 m
Therefore, sides are 18m & 12m.
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Answered by
9
______Heyy Buddy ❤______
_____Here's your Answer _______
Let the length of the side be x m.
=> Perimeter of the square = 4x.
Since, Difference of the two perimeter is 24m.
=> Perimeter of second square = 24 + 4x m.
And, Length of side of second square = (24 + 4x)/4
=> side of other Square = 6 + x m.
Area of sum of two square = 468 m^2.
A.T.Q.
=> x^2 + ( 6 + x)^2 = 468
=> x^2 + 36 + x^2 + 12x = 468
=> 2x^2 + 12x = 432
=> 2x^2 + 12x - 432 = 0
=> x^2 + 6x - 216.
So, x^2 + 6x - 216 is the quadratic equation to find the side of the square.
✔✔✔
_____Here's your Answer _______
Let the length of the side be x m.
=> Perimeter of the square = 4x.
Since, Difference of the two perimeter is 24m.
=> Perimeter of second square = 24 + 4x m.
And, Length of side of second square = (24 + 4x)/4
=> side of other Square = 6 + x m.
Area of sum of two square = 468 m^2.
A.T.Q.
=> x^2 + ( 6 + x)^2 = 468
=> x^2 + 36 + x^2 + 12x = 468
=> 2x^2 + 12x = 432
=> 2x^2 + 12x - 432 = 0
=> x^2 + 6x - 216.
So, x^2 + 6x - 216 is the quadratic equation to find the side of the square.
✔✔✔
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