Question

Sum of the areas of two squares is 148.if difference of their perimeter is 24m then dind the sides of the two squares

Answer 1

Answer:

Step-by-step explanation:

Let sides be x and y.

X^2 +y^2 =148 Eq 1

4x -- 4y = 24

X -- y = 6

X = 6 + y

Using in Eq 1

(6 + y)^2 -- y^2 = 148

36 + y^2+2y + y^2 =148

2y^2 + 2y -- 112 = 0

Y^2 +y -- 56 = 0

y^2 +8y -- 7y -- 56 =0

y(y +8) -- 7(y + 8) =0

(y+8)(y -- 7) = 0

y = 7 ( positive value)

X = 6 +7=13

Sides are 13 and 6