Question

Sum of the areas of two squares is 400 cm2. if the difference of their perimter is 16cm find the sides of the two squares?

Answer 1

let the area, perimeter and side of the first square be a1, p1 and s1 respectively.
let the area, perimeter and side of the second square be a2, p2, and s2 respectively,

so, s1^2 + s2^2 = 400
root on both sides
s1 + s2 = 20cm.............1

4s2 - 4s1 = 16
s2-s1 = 4................2

subtracting 2 from 1

2s1= 16
s1 = 8
substituting the value in 2,

s2 = 12