Question

Sum of the cp's of two cars is rs. 1,00,000. 1st car is sold at a profit of 20% and 2nd car is sold at a loss of 20%. however, their sps are same. what is the cp of 1st car?

Answer 1

your answr........................?...

Answer 2

Answer:  The required cost price of first car is Rs. 40000.

Step-by-step explanation:  Given that sum of the cost prices of two cars is Rs. 1,00,000, first car is sold at a profit of 20% and second car is sold at a loss of 20%.

The selling prices of both the cars are same.

We are to find the cost price of the first car.

Let the cost price of first car be Rs. x. Then, the cost price of the second car will be Rs. (100000 - x).

Also, according to the given information, we have

$x+20\%\times x=(100000-x)-20\%\times (10000-x)\\\\\\\Rightarrow x+\dfrac{20}{100}x=(100000-x)-\dfrac{20}{100}(100000-x)\\\\\\\Rightarrow x+\dfrac{x}{5}=(100000-x)-\dfrac{100000-x}{5}\\\\\\\Rightarrow \dfrac{6x}{5}=\dfrac{4(100000-x)}{5}\\\\\Rightarrow 6x=400000-4x\\\\\Rightarrow 6x+4x=400000\\\\\Rightarrow 10x=400000\\\\\Rightarrow x=\dfrac{400000}{10}\\\\\Rightarrow x=40000.$

Thus, the required cost price of first car is Rs. 40000.