Question

sum of the digit if a two digit number is 9. when we inter change the digit , it isfound that the resulting new number isgreater when the original number by 27 . what is the two digit number?
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Answer 1

Step-by-step explanation:

Let the digits be x and y.

Let the digits be x and y.Then, x+y = 9

Let the digits be x and y.Then, x+y = 9the original number is 10x+y.

Let the digits be x and y.Then, x+y = 9the original number is 10x+y.On reversing, we get the new number as 10y+x

According to the question:)

The new number is greater than the old number by 27, i.e.

r by 27, i.e.(10y+x) - (10x+y) = 27

(10y+x) - (10x+y) = 27

(10y+x) - (10x+y) = 27or 9y-9x = 27, or y-x = 3

(10y+x) - (10x+y) = 27or 9y-9x = 27, or y-x = 3and x+y = 9

By adding these two equations, we get 2y = 12 or y = 6.

two equations, we get 2y = 12 or y = 6.Thus, x = 3.

two equations, we get 2y = 12 or y = 6.Thus, x = 3.Therefore, the number will be 3 answer.

Answer 2

Answer:

then x+y = 9........multiply by 9

9x+9y= 81.........1

10y+x = 10x+y+27

9x-9y = -27 ......2

adding 1 and 2

we get.18x = 81+(-27)= 54

X = 54/18 = 3

then y = 6

hence the number was 10x+y = 30+6=36 answer

hope it helps you........

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