Sum of the digit of a two digit no. is 14. If we add 18 to the original no., the digits interchange their places. Write two equations for these two statements.
Answers
Answered by
1
68 is the answer
6+8=14
68+18=86
6+8=14
68+18=86
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Answered by
3
Let the tens digit = x
and unit digit = y
Original no. = 10x + y
Interchanging digit = 10y + x
ATQ
10x+y+18 = 10y + x
9x-9y = 18
9(x-y)= 18
y-x = 2
y- x = 2 is the first equation
We have given
The sum of the digit of two digit no is 14
that is
x + y = 14
this is 2nd equation.
and unit digit = y
Original no. = 10x + y
Interchanging digit = 10y + x
ATQ
10x+y+18 = 10y + x
9x-9y = 18
9(x-y)= 18
y-x = 2
y- x = 2 is the first equation
We have given
The sum of the digit of two digit no is 14
that is
x + y = 14
this is 2nd equation.
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