Sum of the digit of a two digit number is 11 when we interchange the digit it is found that the resulting new number is greater than the original number by 9 find the two digit number.
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shizashaheem:
Which one is the right answer?
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let the units digit be x
and tens digit = 11-x
no. = (11-x)×10+x
=110-10x +x
=110-9x
interchanging no. =x×10+11-x
=10x+11-x
= 9x+11
a/q 9x+11-(110 -9x)=9
9x+11-110+9x=9
18x- 101=9
18x=9+101
18x=110
x =110 ÷18
x=6.11
then original no. =110-9×6.11
=110- 54.99
= 110-56
= 45 ans
and tens digit = 11-x
no. = (11-x)×10+x
=110-10x +x
=110-9x
interchanging no. =x×10+11-x
=10x+11-x
= 9x+11
a/q 9x+11-(110 -9x)=9
9x+11-110+9x=9
18x- 101=9
18x=9+101
18x=110
x =110 ÷18
x=6.11
then original no. =110-9×6.11
=110- 54.99
= 110-56
= 45 ans
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