Question

sum of the digit of a two digit number is 9 when the digits are reversed it is found that the resulting number is greater than the original number by 27 find the number

Answer 1

two digit no 10x + y
Sum of digits x +y =9
If add 27 to its revers the no
10x +y +27 =10y + x
y-x=3, x=3 ,y =6

Answer 2

${ hey dear }$


Here is your answer



Let the number be x and y

The original number is ( 10y + x)

Number obtained by reversing the digits
( 10x + y)


given that sum of digit of number is 9


That is x + y = 9. ( 1 )


Second condition obtained by reversing the digit resulting number is greater than its original number by 27


That is

( 10 x + y ) = ( 10y +x) 27


10x + y - 10y - x = 27

9x - 9y = 27

x - y = 3 .. ( 2)

x +y = 9
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2x = 12

x = 12 / 2

x= 6


Put x =6 ( 1 ) in we get

6 + y =9

y = 9 - 6

y = 3


The original number = 10 y + x

10 ( 3 ) +6 = 30 + 6 = 36


${ answer is 36 }$


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hope it helps


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