Question

Sum of the digits in the product of (16^100)*(125^135)is

Answer 1

((2^400)*(5^405))

((2^400)*(5^400)*(5^5))

((2*5)^400)*(5^5))

((10^400)*(5^5))

as we know that 10^n= 10000......

so ((1000....)*(3125))

we get 312500000.....

ans=3+1+2+5+0+0+0..... =11

Answer 2

Answer:

Sum of the digits in the product of expression is 11.  

Step-by-step explanation:

Given : Expression $(16^{100})\times (125^{135})$

To find : Sum of the digits in the product of expression ?

Solution :

Expression $(16^{100})\times (125^{135})$

We solve the expression by taking power,

$=(2^{4\times 100})\times(5^{3 \times 135})$

$=(2^{400})\times(5^{405})$

$=(2^{400})\times(5^{400}\times5^{5})$

$=((2 \times 5)^{400})\times(5^{5})$

$=((10)^{400})\times(3125)$

Since $10^n = 10000000...$

$=312500000....$

Now, The sum of the digits is 3+1+2+5+0+0....+0=11

Therefore, Sum of the digits in the product of expression is 11.