What os the amount of compound interest on 27500 at tje rate of 16% for 2 years?
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A = P(1 + R/100)^t
A = 27500 (1 + 16/100)^2
A = 27500 ( 100+16/100)^2
A = 27500 × 116/100 × 116/100
A = 3700400/100
A = 37004 ruppes
CI = 37004 - 27500
CI = 9504 rupees
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A = 27500 (1 + 16/100)^2
A = 27500 ( 100+16/100)^2
A = 27500 × 116/100 × 116/100
A = 3700400/100
A = 37004 ruppes
CI = 37004 - 27500
CI = 9504 rupees
Hope it helped you plzz mark as brainlagist
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