Sum of the digits is also divisible by 9 "induction"
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if n1 is a multiple of 9, take the sum of n1's digits. Let this sum = n2, then sum n2's digits and repeat until nk=9.
How would I use induction to prove that nk=9 for large enough k
my attempt:
base case: n1=r9, where r=1, then for k=1, nk=9
I have trouble finding the induction hypothesis for this question, I do know that 9|n1 and n1≡0(mod9)
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