Question

Sum of the digits of 2 digit number is 10 while when digits are reversed number decreases by 54 find changed number

Answer 1

let the digit in ones place be x

and the digit in tens place be y

therefore, the two digit no. = 10y+x

the reversing no. = 10x+y

A/Q,

x+y=10

=>x=10-y

and,

10y+x-54=10x+y

=>10y-y+x-10x=54

=>9y-9x=54

=>y-x=54/9

=> y - (10 - y) = 6

=> y - 10 + y = 6

=> 2y-10=6

=>2y=6+10

=>y=16/2=8

therfore, x = 10-8 = 2

the no. = 10*8+2 = 82

and the reversing no. = 10*2+8 = 28

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