Sum of the digits of a 2- digit number is 10 . the number is decreased by 36 if the digits are reversed. Find the number
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x+y=10
10x+y-36=10y+x
x=10-y
10(10-y)+y-36=10y+10-y
100-10y+y-36=9y+10
64-9y=9y+10
18y=74
y=74/18
there is mistake in the question as digit cannot be in fraction
hope it helps
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