Sum of the digits of a two-digit numb
is 5. When we interchange the digits,
found that the resulting new number
less than the original number by 27.
What is the two-digit number?
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Step-by-step explanation:
let the digit at one's place be y and at tens place be x
no.=10x+y
x+y=5
y=5-x
according to the statement
10x+y-27=10y+x
10x+5-x-27=10(5-x)+x
9x-22=50-9x
18x=72
x=4
y=5-x
y=1
no. is 10x+y
=41
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