Question

sum of the digits of a two-digit number is 11.The given number is less than the number
obtained by inter changing the digits by 9. Find
the number.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

65

Step-by-step explanation:

let x be the tens digit and y be the units digit

Then, 10x + y = 10x + y -9

9y - 9x = -9

y - x = -1

since y + x = 11

Combining these two equations by adding, we get:

2y = 10

y = 5

10(6) + 5 = 65

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