Sum of the digits of a two digit number is 11. The given number is less than
the number obtained by interchanging the digits by 9. Find the number.
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Answered by
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let the tens digit be x and units digit be y x+y=11-------eq2
1ox+y=1oy+x-9
9x-9y=-9
x-y=-1-----------------eq 1
adding both equations
2x=10
x=5
substituting value of x
x-y=-1
5-y=-1
y=6
number 56
1ox+y=1oy+x-9
9x-9y=-9
x-y=-1-----------------eq 1
adding both equations
2x=10
x=5
substituting value of x
x-y=-1
5-y=-1
y=6
number 56
Answered by
0
Two digit number: xy= 10x+y.
Sum of digits: x+y=11
xy is less then yx by 9: xy+9=yx
xy+9=yx
10x+y=10y+x-9
9x-9y=-9
x-y=-1,
So this is the system of equations to be solved:
x + y=11
x - y =-1
x=5, y=6
The number is 56.
Sum of digits: x+y=11
xy is less then yx by 9: xy+9=yx
xy+9=yx
10x+y=10y+x-9
9x-9y=-9
x-y=-1,
So this is the system of equations to be solved:
x + y=11
x - y =-1
x=5, y=6
The number is 56.
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