sum of the digits of a two-digit number is 5 when the digits are reversed the resulting number is greater than the original number by 27 find the number
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Let the number be 10x+y
x+y = 5 …(1)
10x+y-(10y+x) = 27, or
10x-x-10y+y= 27, or
9x-9y = 27, or
x-y = 3 …(2)
Add (1) and (2)
2x= 8, or
x = 4 and y = 1
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