Math, asked by varshayadav66, 11 months ago

Sum of the digits of a two-digit number is 9. When we interchange the digits, it is
found that the resulting new number is greater than the original number by 27. What
is the two-digit number?​

Answers

Answered by vikram991
3

Given,

  • Sum of the digits of a two digit number is 9 .
  • When we interchange the digits then the resulting new number is greater then the original number by 27.

To Find,

  • Two Digit Number

Solution,

⇒Suppose the digit at the ten's place be x

And, Suppose the digit at the one's place be y

Therefore,

  • Two Digit number = 10a + b
  • Interchange the number = 10b + a

According to the First Condition :-

  • Sum of the digits of a two digit number is 9 .

\implies \sf{x + y = 9}

\implies \boxed{\sf{y = 9 - x}}

According to the Second Condition :-

  • When we interchange the digits then the resulting new number is greater then the original number by 27.

\implies \sf{10x + y + 27 = 10y + x}

\implies \sf{10x - x + 27 = 10y - y}

\implies \sf{9x + 27 = 9y}

\implies \sf{9x - 9y = - 27}

\implies \sf{9x -9(9 - x) = -27}

(Put the value of y From the Equation First )

\implies \sf{9x -81 + 9x = -27}

\implies \sf{18x = 27 + 81}

\implies \sf{18x = 54}

\implies \sf{x = \dfrac{54}{18}}

\implies \boxed{\sf{x = 3}}

Now Put the value of x in First Condition :-

\implies \sf{y = 9 - x}

\implies \sf{y = 9 - 3}

\implies \boxed{\sf{y = 6}}

Therefore,

\boxed{\sf{\red{Two \ Digit \ Number = 10x + y = 10(3) + 6 = 36}}}

\rule{200}2

Answered by MissKalliste
3

Answer:

\bullet\large\underline\textsf{The\:two\:digit\:number\:is\:36}

\bullet\large\underline\textsf{One's\:place = 3}

\bullet\large\underline\textsf{Ten's\:place = 6}

Step-by-step explanation:

\large\underline\textsf{Given, }

Given,

  • Sum of two digit number = 9

\large\underline\textsf{To\:Find, }

  • Two digit number = ?

\large\underline\textsf{Solution\::}

↦ Let the unit's digit to be x

↦ Let the ten's digit to be (9 - x)

↦ Now, let the original number :

10(9 - x) + x = 90 - 10x + x = 90 - 9x

↦ On interchanging the digits, the new number is :

10x + (9 - x) = 10x + 9 - x = 9x + 9

\large\underline\textsf{According\:to\:the\:question}

New number = Original number + 27

⇝ 9x + 9 = 90 - 9x + 27

⇝ 9x + 9 = 117 - 9x

⇝ 9x = 117 - 9 - 9x

⇝ 9x + 9x = 108

⇝ 18x = 108

⇝ x = 108/18

⇝ x = 6

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So, now we will find out our original number/two digit number :

Original number = 90 - (9 × 6) = 90 - 54 = 36

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Know More On :

• https://brainly.in/question/16910451

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