Sum of the digits of a two-digit number is 9. When we interchange the digits, it is found that the resulting new number is greater than the original number by 27. What is the two-digit number?
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Question :-
- Sum of the digits of a two-digit number is 9. When we interchange the digits, it is found that the resulting new number is greater than the original number by 27. What is the two-digit number?
Given :-
- Sum of the digits of a two-digit number is 9. When we interchange the digits, it is found that the resulting new number is greater than the original number by 27.
Find Out :-
- What is the two-digit number?
Solution :-
⊙ Let us assume the digit of units place = x
⊙ Then the digit of tens place will be = (9 – x)
⊙ Thus, the two-digit number is 10(9 – x) + x
⊙ Let us reverse the digit the number becomes 10x + (9 – x)
So, according to the question or ATQ :-
➙ 10x + (9 – x) = 10(9 – x) + x + 27
➙ 9x + 9 = 90 – 10x + x + 27
➙ 9x + 9 = 117 – 9x
On rearranging the terms we get,
➙ 18x = 108
➙ x =
➙ x = 6
✭ So the digit in units place = 6
✭ Digit in tens place is
➙ 9 – x
➙ 9 – 6
➙ 3
Henceforth, the number is 36
Answered by
30
Given :
- Sum of the digits of a two-digit number is 9.
- When we interchange the digits, it is found that the resulting new number is greater than the original number by 27.
To Find :
- What is the two-digit number?
Solution :
let,
- Digit at ten's place be x
- Digit at one's place will be 9 - x
Original number :-
New number :-
- It is given that the resulting new number is greater than the original number by 27.
According to question :-
Now ,
- Ten's place digit = x = 3
- One's place digit = 9 - x = 9 - 3 = 6
Number = 36
Hence, the number is 36.
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