Question

Sum of the digits of a two-digit number is 9. When we interchange the digits, it is

found that the resulting new number is greater than the original number by 27. What

is the two-digit number?​

Answer 1

let the 2 digit number be x

tens place digit=9-x 2-digit number=10x tens place unit +unit place digit.

original number=10(9-x)+x

new number : according to the question .

original number=27

10x+(9-x)=10(9-x)+x+27

10x+9-x=90-10x+x+27

9x+9=117-9

18x-108

x=108/18=6

2digit number=10(9-x)+x

=10(9-6)+6

10*3+6=30+6=36

hence the 2digit number is 36

HOPE IT HELPED U

Answer 2

Answer:

$\huge\green{\boxed{\sf Answer}}$

Given

The sum of the two digits = 9

On interchanging the digits, the resulting new number is greater than the original number by 27.

Let us assume the digit of units place = x

Then the digit of tens place will be = (9 – x)

Thus the two-digit number is 10(9 – x) + x

Let us reverse the digit

the number becomes 10x + (9 – x)

As per the given condition

10x + (9 – x) = 10(9 – x) + x + 27

⇒ 9x + 9 = 90 – 10x + x + 27

⇒ 9x + 9 = 117 – 9x

On rearranging the terms we get,

⇒ 18x = 108

⇒ x = 6

So the digit in units place = 6

Digit in tens place is

⇒ 9 – x

⇒ 9 – 6

⇒ 3

Hence the number is 36