Question

sum of the digits of a two digit number is one fourth of the number if the digits are reversed the number thus formed is 18 more than the original number find the number

Answer 1

Supp. one digit no.= x
two digit no.= y
Original no. is x+10y
New no. is 10y+x

Sum of the digits of two digit no. is 1/4 of the number.
x+y=1/4- eq. 1
4x+4y=1
If the digits are reversed the no. thus formed is 18 more than the original number.

10y+x=18 eq.2

From 1 and 2
4x+4y=1
10y+x=18 .

Now solve this eq. by Elimination method.