sum of the digits of a two-year digit number is 12. If the digits are reversed, the new number so formed increases by 36. find the number.
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let the digit at one's place=y
let the digit at ten's place=x
two digit number =xy
=10x+y
reverse=10y+x
A.T.Q
x+y=12--------------1
10y+x=10x+y+36
10y-y+x-10x=36
9y-9x=36
9(x-y) =36
x-y=4---------------2
1+2
x+x-y+y=12+4
2x=16
x=8
put x=8 in 1
y=12-8
y=4
Therefore, the two digit number is 84.
Hope it helps you.....
let the digit at ten's place=x
two digit number =xy
=10x+y
reverse=10y+x
A.T.Q
x+y=12--------------1
10y+x=10x+y+36
10y-y+x-10x=36
9y-9x=36
9(x-y) =36
x-y=4---------------2
1+2
x+x-y+y=12+4
2x=16
x=8
put x=8 in 1
y=12-8
y=4
Therefore, the two digit number is 84.
Hope it helps you.....
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