Sum of the digits of the two digit number is 10. When we interchange the digits we will get a new number which is greater then the original number by 18. Find the original number.
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It's given that=a+b=10
Original number=10a+b
Number formed by interchanging its digit
=10b+a
Now,
According to the question
=(10b+a)-(10a+b)=18
=10b +a-10a-b=18
=9b-9a=18
=9(b-a)=18
=b-a=2
Now, by subtacting b-a=2 from a+b=10
we get 2a=8
a=4
Now,Since we know that:-
a+b=10
4+b=10
b=10-4
Hence, the oringinal number=46(Answer)
I hope this will help u.. :)
Original number=10a+b
Number formed by interchanging its digit
=10b+a
Now,
According to the question
=(10b+a)-(10a+b)=18
=10b +a-10a-b=18
=9b-9a=18
=9(b-a)=18
=b-a=2
Now, by subtacting b-a=2 from a+b=10
we get 2a=8
a=4
Now,Since we know that:-
a+b=10
4+b=10
b=10-4
Hence, the oringinal number=46(Answer)
I hope this will help u.. :)
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