Question

sum of the first 14 yerm of an arithametic progress is 1050 an its first term is 10 find the 20th term​

Answer 1

Answer:

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Answer 2

Given,

S₁₄₌1050, a=10, a₂₀=?

We know that

Sₙ=n/2(a+aₙ)

⇒S₁₄=14/2(10+a₁₄)

⇒1050=7(10+a₁₄)

⇒10+a₁₄=150

⇒a₁₄=140

⇒a+13d=140 ( Using:aₙ=a+(n-1)d )

⇒10+13d=140 ( Putting a=10)

⇒13d=130

⇒d=10

Now,

a₂₀=a+19d ( Using:aₙ=a+(n-1)d )

⇒a₂₀=10+19(10) ( Putting a=10 and d=10)

⇒a₂₀=200.