sum of the five consecutive multiples of 4 is 222 find these multiples
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= let the consecutive numbers be x, x+4,x+8,x+12,x+16
=5x+40=222
=5x = 222-40
=5x = 182
=x = 182/5
=x = 36.4
ans = 36.4 ,40.4 ,44.4 ,48.4 , 52.4
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Let , five cosecutive multiple of 4 are x , x+4 , x+8 , x+12 , x+16.
Their sum = 5x +40.
5x+40 =222.
X = 36.4
Numbers are .... 36.4 , 40.4 , 44.4 , 48.4 , 52.4
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