Sum of the interior angle of the polygon is 10 right angle how many sides has the polygon
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Answered by
1
Answer:
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Answered by
1
Answer:
Sum of interior angles of polygon =10 right angles =10×90
o
=900
o
(given)
But sum of interior angles of a polygon =(2n−4) right angles.
i.e.900=(2n−4)×90
o
⇒180n−360=900
⇒180n=900+360
⇒n=
180
1260
⇒n=7
Hence the required number of sides =7
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