Sum of the natural numbers between 1 to 101 divisible by 2 or 5 is
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The natural number which are divisible by 2 and 5 are 10, 20, 30,........................,100 a=10 , d=10 , nth term= 100 Find sum and nth term an= a+* (n-1)d
100=10+(n-1)10
100=10+10n-10
100=10n
n=100/10
n=10
sn=n/2(a+l)
sn=10/2(10+100)
sn=5(110)
sn=550
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