Question

sum of the numrator and denominator of a fraction is 10.if both are increased by 1 , the friction becomes equal to 1\2 .find the original friction​

Answer 1

Step-by-step explanation:

Let the numerator be x and the denominator be y.

From the given information, we have,

x+y=18andy+2x=31or,x+y=18=>y=18−x....(i)Also,y+2x=31=>3x=y+2=>3x−y−2=0....(ii)

Solving by substitution method,

Substituting (i) in (ii), we get,

3x−y−2=0=>3x−18+x−2=0=>4x=20=>x=5

Putting x=5 in equation (i), we get,

y=18−x=>y=18−5=>y=13

Thus, the original fractyion is yx=135

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