sum of the present age of father and son is 45. after 10 years father age will be 5 more than twice the age of the son . find their ages
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let the present ages of son and father be x,y...
given that,
x+y=45
x=45-y
after 10 years age of father =X+10
age of son =2y+5
x+10=2y+5
45-y+10=2y+5
3y=55-5
3y=50
y=50/3
hey my answer may be wrong .......
EXTREMLY SORRY. .....
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