Sum of the present ages of Manish and Savita is 31. Manish’s age 3 years ago
was 4 times the age of Savita. Find their present ages.
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Answer:
Let, the age of Manish = a Sum of their ages is 31 year:
age of Savita = b
+ a + b = 31
- a = 31 - b .. (1)
3 years ago
Manish's age = (a - 3) years Savita's age = (b - 3) years
In question: that time
- Manish = 4 * Savita
(a - 3) = 4(b - 3)
+ a - 3 = 4b - 12 =
+ a -4b = - 12 + 3
(31 - b) - 4b = 9
+ 31 - 5b = -9
{a=31 - b} b = 8
- 31 + 9 = 5b 40 = 5b
(40/5) = b
Putting the value of x in equation 1,
+ a = 31 - 8 = 23 year
Age of manish = a =23 years
Age of manish = a =23 years Age of savita = b = 8 years
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