Math, asked by anandbabug, 11 months ago

Sum of the series (x-y)^2+x^2+y^2+(x+y)^2+......+[(x+y)^2+6xy] is

Answers

Answered by jayantsingh94
1

Answer:

Here , no. of terms in the given A.P. =n=6

1st term = a= (x-y)^2

& d = 2xy

so, sum of the given AP is

S = 3[ 2(x-y)^2 + (6-1)×2xy] = 3[2(x-y)^2 + 10xy]= 6(x-y)^2+30xy ans.

Thank you!!

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