sum of the square of five consecutive wwnatural number is 1455 find the numbers
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let the numbers be n, n+1,n+2,n+3,n+4
n²+(n+1)²+(n+2)²+(n+3)²+(n+4)²=1455
n²+n²+1+2n+n²+4+4n+n²+9+6n+n²+16+8n=1455
5n²+20n+30=1455
5n²+20n=1455-30=1425
5n²=1425-20n
5n=1425-20=1405
5n=1405
n=1405/5
n=281
5 consecutive numbers are 281,282,283,284,285
n²+(n+1)²+(n+2)²+(n+3)²+(n+4)²=1455
n²+n²+1+2n+n²+4+4n+n²+9+6n+n²+16+8n=1455
5n²+20n+30=1455
5n²+20n=1455-30=1425
5n²=1425-20n
5n=1425-20=1405
5n=1405
n=1405/5
n=281
5 consecutive numbers are 281,282,283,284,285
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