Sum of the square of two consecutive positive even integers is 100 ,find those numbers by using quadratic equations.
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Answer:
let one no. be = x
other will be =(x+2)
ATQ
x^2+(x^2+4+4x) = 100
2x^2+4+4x= 100
2x^2+4x-96 =0
x^2+2x-48 =0
now after solving this
we get
x =6,8
so the required numbers are 6 , 8
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