Sum of the squares of two consecutive even numbers is 452.
a) If one number is 'x' , then what is the next number ?
b) Form the second degree equation and find the numbers
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Answer:
a) x+2
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Answer:
Given:
Sum of squares of 2 consecutive even numbers is 452.
One number is x.
Answer:
Let the two consecutive even numbers be x and (x+2).
Now,
According to the question
=> x²+(x+2)²=452
{using (a+b)²= a²+b²+2ab}
we get,
=> x²+ x²+4x+4=452
=> 2x²+4x+4-452=0
=> 2x²+ 4x-448=0
=> 2 ( x² +2x - 224) = 0
=> x² +2x - 224=0
By splitting the middle term
we get,
=> x² + 16x- 14x - 224=0
=> x(x+16) -14(x+16)=0
=> (x-14) (x+16)
=> x= 14 and x = -16
As we cannot take negative value
so x=14 and the other number is 16. (14+2)
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