Sum of the squares of two consecutive positive even integers is 100,find those numbers by using quadratic equations
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Answer:
6 and 8.
Step-by-step explanation:
let ist no is = x
let 2nd no is= x+2. (because no are even integers)
given,
x²+(x+2)²=100
x²+x²+4+4x=100
2x²+4x-96=0
x²+2x-48=0
x²+8x-6x-48=0
x(x+8)-6(x+8)=0
(x-6)(x+8)=0
x-6=0,(x+8=0
x=6, x=-8reject
x=6
2ndno=x+2=6+2=8
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