Question

Sum of the three consecutive numbers is 1956 what is 23 of the highest number

Answer 1

1. Answer : A)150.19

Explanation :

X+x+1+x+2 = 1956

3x = 1956 – 3 = 1953

X = 1953/3 = 651

X+3 = 653

23% of largest num = 23*653/100 = 150.19

Answer 2

Correct question is "Sum of the three consecutive numbers is 1956 what is 23% of the highest number ?"

Answer:

23% of the highest number is 150.19

Step-by-step explanation:

Given sum of the three consecutive numbers is 1956.

Let, three consecutive numbers be x,(x+1),(x+2).

According to question sum of x,(x+1),(x+2) is 1956.

So,

$x + (x + 1) + (x + 2) = 1956$

We are removing first bracket,

$x + x + 1 + x + 2 = 1956$

We are separating variable and constant part,

$x + x + x = 1956 - 2 - 1 \\ 3x = 1953 \\ x = \frac{1953}{3} \\ x = 651$

So, value of x is 651.

Therefore three consecutive numbers are 651, 652 and 653.

Here highest number is 653.

Now we want to find value of 23% of the highest number.

$23\% \: of \: 653 \\ = \frac{23}{100} \times 653 \\ = 150.19$

This is a problem of percentage.

Know more about percentage.

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