sum of the three terms of an AP is -6 and the product is 64 find the 'a'terms
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a values are. 8 and -4
Goku1203:
I want an solved answer
a+a+2d+a+3d= -6. 3a+3d= -6. a+d=. -2. a(a+d)(a+2d)=64. a(-2)(a+2d)=64. a^2 +2ad= -32. a^2+2a(-2-a)= -32. a^2-4a-2a^2= -32. -a^2-4a= -32. a^2 +4a+32=0. a^2 +8a-4a+32=0. (a+8)(a-4)=0. a= 4, -8
answer is 4, -8
sorry after submitting once i don't get any option to upload my solvation paper
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