Question

sum of the two digit number and the number formed by reversing the order of digits is 88 if difference of digits is 2 and the unit digit is greater determine the number.

Answer 1

Let x = the 10's digit
Let y = the units

"the sum of a two digit number and the number formed by reversing the order digits is 88."

(10x + y) + (10y + x) = 88
11x + 11y = 88

Simplify, divide by 11
x + y = 8

"if difference of the digits is 2 and the units digit is greater."

y - x = 2

Adding eliminates x, find y

2y = 10
y = 5

then

y-x = 2

5-2 = x

x = 3




5 - 2 = 3 is 10's digit
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35
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the sum of a two digit number and the number formed by reversing the order digits is :-


35 + 83 = 88 

Answer 2

Let the two digit number be 10x+y
If we reverse the order the nee digit so formed is 10y+x

According to the question

10x+y+10y+x = 88
11x+11y = 88
11(x+y) =88
x+y = 8........(1)

However,
It is given,
y-x = 2 ....... (2)

Adding (1) and (2)
2y = 10
y = 5

Put y =5 in any equation to get x =3

So the number is 35