Question

Two bulbs rated (60W,220V) and (40W,220V) are connected in series. Which one of the two will fuse first?

Answer 1

40w,220v is fuse first

Answer 2

40W bulb will fuse first
reason is:
P=v*i
   =v*(v/r)
   =v^2/r
R=P/v^2
resistance of first bulb is 806 ohms
resistance of second bulb is 1210 ohms
as they are connected in series the voltage will be 440 V
I=440/(806+1210)=0.21A
voltage drop across  60 W bulb will be V=I*R
V=0.21*806
  =175V
voltage drop across 40W bulb is
V=0.21*1210
 =254V
As it has high voltage 40W bulb will fuse first