Math, asked by parsewar, 1 year ago

sum of the two digit number is 9. the number obtained by interchanging the digits exceeds the given number by 27. find the original number.

Answers

Answered by Hetarth4
6
Let the digit on one's place be x
Let the digit on ten's place be y

The original number :- 10y+x

From the data :- x+y=9----------equation 1

Now if we interxhange the digit i.e.
let the digit on one's place be y
Let the digit on ten's place be x

The new number :- 10x+y

From the data :-10x+y = 10y+x+27
=10x-x=10y-y+27
=9x=9y+27
=9x-9y=27
=x-y=3--------------equation 2

Now adding equation 1 and equation 2
x+y=9
x-y=3
we will get 2x=12==>x=6

Substituting value of x in equation 1
x+y=9
y=9-6
y=3

ANSWER:-x=6 and y=3

If you find it helpful please mark it as braineliest......

parsewar: because it is not giving option to mark as brainliest
Hetarth4: it will be on the top of my answer
parsewar: no it is not there
Hetarth4: no problem check later on
parsewar: OK
parsewar: thanks once again for giving right answer
Hetarth4: thank you
Hetarth4: oops
Hetarth4: i should say welcome
Hetarth4: The origunal number :- 10y+x=30+6 =36
Answered by Raghav3333
7
hi

let the number be xy

tens place = 10x

ones place = y

Sum of the two digit number is 9

x + y = 9.........[1]

the number obtained by interchanging the digits exceeds the given number by 27

so let

 form an equation

10 x +y = 10y +x + 27

10x +y -10y -x = 27

=>  9x - 9y= 27

let us divide by 9

=> x - y = 3.......[2]

on adding [1] and [2]

x + y =9

x - y = 3

2x = 12

x = 6

y = 9 -x

=> 9 - 6

=>3

x = 6 and y= 3

original no. = xy

=>63

hope it helps u

:)


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