sum of the two digits of two digit number is 9 when we interchange the digits, it is found that the resulting number is greater than the original number is 22 what is the two digit number plz help
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Assume the digit in ones place as x and the digit in tens place is y The original number is (10y + x) Number obtained by reversing the digits = (10x + y) Now check for the condition Given that sum of digits of the number is 9 That is x + y = 9 → (1) Second condition is, number obtained by interchanging the digits is greater than the original number by 27 That is (10x + y) = (10y + x) 27 ⇒ 10x + y – 10y – x = 27 ⇒ 9x – 9y = 27 ∴ x – y = 3 → (2) Add (1) and (2), we get x + y = 9 x – y = 3 ----------- 2x = 12 ∴ x = 6 Put x = 6 in (1), we get 6 + y = 9 ⇒ y = 9 – 6 = 3 The original number = 10y + x = 10(3) + 6 = 36
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