sum of the two number is 106 . if greater number is divided by smaller number then the quotient is 2 and remainder is 19 find the number by completing activity the greater number M and smaller number be n.
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let the required two numbers be x and y such that x>y.
now, it is given that
x+y= 106 ...........(I)
and , x = y×2+19
or, x = 2y+19
or,. x-2y= 19 ............(ii)
By subtracting eq.1 from 2 ,we get
so, (x-2y)-(x+y)=19-106
x-2y-x-y= -87
-3y= -87
y=29
then x= 106-y=106-29=106-29= 77
Hence ,the two numbers are 77 and 29.(sorry for not taking M and n as the required numbers. So please do not mind for it)
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